Learning 8086 Assembly Language: Environment Setup, Sample Program, Registers, Instruction Classification, and Execution Mechanism
This tutorial guides readers through installing a DOS environment, writing and analyzing a simple 8086 assembly program, understanding pseudo‑instructions, registers, instruction categories, execution flow, and data addressing, providing links and code examples for hands‑on learning.
Through a concise 8086 assembly language tutorial, readers gain low‑level programming experience and a deep understanding of how a machine executes programs.
Environment installation : Use VirtualBox with a DOS ISO or DOSBox; create a custom ISO (e.g., hdiutil makehybrid -o masm.iso ./mas ) and mount it. Useful links include the source code download page and an assembly forum.
Simple program example (shown below) demonstrates pseudo‑instructions (assume, segment, end), data and stack segments, and calls to subroutines for string length, case conversion, and reversal:
assume cs:code,ds:data,ss:stack
data segment
db 'hello world'
db 16 dup(0)
data ends
stack segment
db 32 dup(0)
stack ends
code segment
start: mov ax, data
mov ds, ax
call strlen ; BX = 0BH (11)
call strtoupper ; convert to uppercase
call strrev ; reverse string
mov ax,4c00h
int 21h
strlen: mov bx, 0
s: mov al, ds:[bx]
cmp al, 0
jne next
ret
next: inc bx
loop s
strtoupper: mov cx, bx
mov si, 0
s1: mov dl, byte ptr [si]
cmp dl, 65 ; 'A'
ja next1
ss1: mov byte ptr [16+si], dl
inc si
loop s1
ret
next1: and dl,11011111b
jmp ss1
strrev: mov ax, stack
mov es,ax
mov cx, bx
mov di, bx
mov si, 0
mov bx, data
mov ds, bx
mov bx, 16
s2: mov al, ds:[bx+si]
mov es:[di], al
inc si
dec di
loop s2
ret
code ends
end startThe program uses pseudo‑instructions (assume, segment, end), assembly instructions, and labels (code, data, s1).
General registers : AX, BX, CX, DX, SI, DI, SP, BP, IP, CS, SS, DS, ES, PSW.
Instruction classification is illustrated with diagrams (not reproduced here) showing categories such as data movement, arithmetic, control flow, etc.
Program execution : Physical address = segment × 16 + offset. Example segment:offset notation (SA+10H:0) is explained with references to textbook pages.
Data addressing and access : 8086 handles byte and word data; explicit byte ptr or word ptr is required for memory accesses without registers.
References: debugging guide (https://thestarman.pcministry.com/asm/debug/debug.htm) and a CSDN article (https://blog.csdn.net/weixin_43809545/article/details/103640185).
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